Anyone please send a Vidyapan on chocolate in Hindi for grade 6
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Using the laws of exponents, the value of: (2)^-3×(1/6)^×(1⁰+2⁰+3⁰)^-2
Explanation:
Using the laws of exponents, the value of: (2)Using the laws of exponents, the value of: (2)^-3×(1/6)^×(1⁰+2⁰+Using the laws of exponents, the value of: (2)^-3×(1/6)^×(1⁰+2⁰+3⁰)^-23⁰)^-2^-3×(1/6)^×(1⁰+2⁰+3⁰)^-2
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