Question

Anyone please solve the given problem

Answer 1

let the number be x

the numerator is 3 less than the denominator then numerator =x-3and denominator be x

2 is added to both of them hence

numerator=x-3+2=x-1

denominator=x+2

x-1/x+2=29/30

cross multiply

=(x-1)×30=(x+2)×29

30x-30=29x+58

30x-29x=58+30

x=88

substitute x value in both numerator and denominator

that is x-1=88-1

=87

x+2=88+2

=90

hence the fraction is 87/90.

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