Math, asked by sejal031, 7 hours ago

Anyone please solve the question- 14​

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Answered by ayushiagarwal694
5

Answer:

 \frac{3cos(90 - 55)}{7sin35}  -  \frac{4(cos70  \times cosec(90 - 20)}{7(tan5tan25tan45tan(90 - 65)tan(90 - 5))}

 \frac{3sin35}{7sin35}  -  \frac{4(cos70 \times sec70)}{7(tan5 \times tan25  \times 1 \times cot25 \times cot5)}

 \frac{3}{7}  - \frac{4 \times 1}{7 \times 1}

 \frac{3}{7}  -  \frac{4}{7}

 -  \frac{1}{7}

Hope this answer will help you.

Thank you

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Answered by llAngelsnowflakesll
3

Answer:-

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