anyone please solve this
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as triangle is issocels so angle BCA is also 65.
so the third angle BAC =180-65-65
=180-130
=50.
but BAC = ACE as corresponding angles
ao ACE =50
now ACE +ECD=180 as linear pair.
ECD= 180- 50
=130
so the third angle BAC =180-65-65
=180-130
=50.
but BAC = ACE as corresponding angles
ao ACE =50
now ACE +ECD=180 as linear pair.
ECD= 180- 50
=130
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