Question

anyone please solve this below question with step by step explanation.



The main scale of Vernier callipers has n divisions/cm. n divisions of the Vernier scale coincide with (n-1) divisions of main scale. the last count of the Vernier callipers is,



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Answer 1

Answer:

OPEN the pic and get your ANSWER

Explanation:

PLZ MARK AS BRAINLIST

Answer 2

ANSWER!

In a Vernier callipers, 1 cm of the main scale is divided into 20 equal parts. 19 divisions of the main scale coincide with 20 divisions on the vernier scale.

BY THIS WAY...

N

N−1

110N

1N−1

Answer :

C

Solution :

Least count = 1 MSD - 1 VSD

(N−1)MSD=N(VSD)⇒VSD=(1−1N)MSD

Least count =1MSD−(1−1N)MSD

=(1N)(1mm)=110Ncm

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