Math, asked by mohdarham38, 5 months ago

Anyone please tell the answer

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Answers

Answered by anubhav082006
0

Step-by-step explanation:

Reena present age = x

Ajay present age=x-6

sum of their ages =28

x+x-6=28

2x -6 =28

2x= 28+6

2x=34

x=34/2

x=17

Reena age =x =17

Ajay age=x-6=17-6=11

Answered by Champion55
4

Given :

⬤ Reena is Six years older than her brother Ajay.

⬤ Sum of their ages is 28 years .

To Find :

⬤ Present Age of Ajay .

Solution :

Let :

  • Age of Ajay be = x
  • Age of Reena be = x + 6

According per Question :

\sf{x+x+6=28}

2x + 6 = 28

2x = 28 - 6

2x = 22

x = 22/2

x = 11

Therefore z The Value of x is 11 .

Now :

Age of Ajay = x

= 11

Age of Reena = x + 6

= 11 + 6

= 17

Hence , Age of Ajay is 11 years and Age of Reena is 17 years .

Option c) is Correct .

Check :

x + x + 6 = 38

11 + 11 + 6 = 28

28 = 28

Hence Checked .

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