Question

anyone plese solve these questions​

Answer 1

Answer:

60° , 30°, 45°

Step-by-step explanation:

(1)

$2 \sin(o) = \sqrt{3}$

$\sin(o ) = \frac{ \sqrt{3} }{2}$

$\sin(o) = \sin(60)$

THEREFORE , theta = 60°

(2)

$\tan(o) = \frac{1}{ \sqrt{3} }$

$\tan(o) = \tan(30)$

THEREFORE , theta = 30°

(3)

$\cos(o) = \frac{1}{ \sqrt{2} }$

$\cos(o) = \cos(45)$

THEREFORE , theta = 45°

Answer 2

Answer:

60 30 45

Step-by-step explanation:

Step-by-step explanation:

(1)

2 \sin(o) = \sqrt{3}2sin(o)=3

\sin(o ) = \frac{ \sqrt{3} }{2}sin(o)=23

\sin(o) = \sin(60)sin(o)=sin(60)

THEREFORE , theta = 60°

(2)

\tan(o) = \frac{1}{ \sqrt{3} }tan(o)=31

\tan(o) = \tan(30)tan(o)=tan(30)

THEREFORE , theta = 30°

(3)

\cos(o) = \frac{1}{ \sqrt{2} }cos(o)=21

\cos(o) = \cos(45)cos(o)=cos(45)

THEREFORE , theta = 45°