anyone pls ans this ques
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HELLO DEAR,
given that:-
(a-b)x+(a+b)y=a²-b²-2ab --------------(1)
(a+b)(x+y)=a²+b²
=> (a+b)x + (a+b)y = a²+b² ---------------(2)
from--(1) and--(2)
(a-b)x+(a+b)y=(a²-b²-2ab)
(a+b)x + (a+b)y =( a²+b²)
(-)..........(-)................(-)
___________________________
(a-b)x- (a+b)x = a²-b²-2ab-( a²+b²)
=> ax-bx-ax-bx=a²-a²-b²-b²-2ab
=> -2bx= -2b²-2ab
=> -bx=-b²-ab
= > x=(a+b) put in ---(1)
we get,
(a-b)x+(a+b)y=a²-b²-2ab
=> (a-b)(a+b)+(a+b)y=a²-b²-2ab
=> a² - b²+ (a+b)y =a²-b²-2ab
=> (a+b)y =a²-b²-2ab-a²+b²
=> (a+b)y = -2ab
= > y= -2ab/ (a+b)
I HOPE ITS HELP YOU DEAR,
THANKS
given that:-
(a-b)x+(a+b)y=a²-b²-2ab --------------(1)
(a+b)(x+y)=a²+b²
=> (a+b)x + (a+b)y = a²+b² ---------------(2)
from--(1) and--(2)
(a-b)x+(a+b)y=(a²-b²-2ab)
(a+b)x + (a+b)y =( a²+b²)
(-)..........(-)................(-)
___________________________
(a-b)x- (a+b)x = a²-b²-2ab-( a²+b²)
=> ax-bx-ax-bx=a²-a²-b²-b²-2ab
=> -2bx= -2b²-2ab
=> -bx=-b²-ab
= > x=(a+b) put in ---(1)
we get,
(a-b)x+(a+b)y=a²-b²-2ab
=> (a-b)(a+b)+(a+b)y=a²-b²-2ab
=> a² - b²+ (a+b)y =a²-b²-2ab
=> (a+b)y =a²-b²-2ab-a²+b²
=> (a+b)y = -2ab
= > y= -2ab/ (a+b)
I HOPE ITS HELP YOU DEAR,
THANKS
Harsh2507:
thank u
welcome
:-)
plz mark as brainliest dear
already marked
no
ok
wait
sorry..by mistake marked another one
but the ques where you have answered both ques..that i have marked as brainliest
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