Question

Anyone pls answer this fast

Answer 1

LHS

secΘ+tanΘ-1/tanΘ-secΘ+1

=(1/cosΘ+sinΘ/cosΘ-1)/(sinΘ/cosΘ-1cosΘ+1)

=1+sinΘ-cosΘ/sinΘ-1+cosΘ

=1+sinΘ-cosΘ(1-sinΘ)/sinΘ-1+cosΘ(1-sinΘ)

=1-sinΘ+sinΘ-sin²Θ-cosΘ+sinΘcosΘ/sinΘ-1+cosΘ(1-sinΘ)

=cos²Θ-cosΘ+sinΘcosΘ/sinΘ-1+cosΘ(1-sinΘ)

=cosΘ(cosΘ-1+sinΘ)/sinΘ-1+cosΘ(1-sinΘ)

=cosΘ/1-sinΘ

RHS

cosΘ/1-sinΘ

hence proved

Answer 2

Answer:

U have to divide it . the first one with the last one and the second one with the first one