anyone plz answer the question
Attachments:
Answers
Answered by
0
yeaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa i know the answer
Answered by
1
Formula of Work done = q (∆V)
(Voltage at infinity -> 0)
Work done to bring q form infinity to A,
10 = 2 (V at point A - V at infinity )
10 = 2 (V at point A - 0 )
V at point A = 10/2 = 5 V.
Similarly, work done to bring q form infinity to B,
20 = 2 (V at point B - V at infinity )
V at point B = 10 V.
Now,
V at point B - V at point A = 10 - 5 = 5 V
Work done to move q form A to B is
W = q (∆V)
W = 2 ( 10 - 5 )
W = 2 (5)
W = 10 J.
(Voltage at infinity -> 0)
Work done to bring q form infinity to A,
10 = 2 (V at point A - V at infinity )
10 = 2 (V at point A - 0 )
V at point A = 10/2 = 5 V.
Similarly, work done to bring q form infinity to B,
20 = 2 (V at point B - V at infinity )
V at point B = 10 V.
Now,
V at point B - V at point A = 10 - 5 = 5 V
Work done to move q form A to B is
W = q (∆V)
W = 2 ( 10 - 5 )
W = 2 (5)
W = 10 J.
sanjay270899:
If you have any doubt in my given solution then comment here...
Similar questions