Question

Anyone plz explain me how 3+ root 6+ root 6+2 occured in the equation.tell me fast.any intelligent student can help me?

Answer 1

$when \: we \: multiply \: any \: under root \: number \: for \: eg \: \sqrt{5} \times \: \sqrt{5} then \: the \: answer \: will \: be5.here \: \sqrt{3} \times \sqrt{3} = 3and \sqrt{3} \times \sqrt{2 } = \sqrt{6} + \sqrt{3} \times \sqrt{2} = \sqrt{6} + \sqrt{2} \times \sqrt{2} = 2$

Answer 2

Because √3×√3=3  Similarly, √2×√2=2 And √3×√2=√6 So when we multiply (√3+√2) by √3 we get 3+√6 and (√3+√2) by √2we get √6+2