anyone plz help in solving the problem
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Answered by
3
here I using formula cot(90- theta)= than( theta)= cot(90-2A)= cot(A-18)
= 90-2A= A-18
= 90+18=A+2A
=108=3A
108/3=A
36=A
= 90-2A= A-18
= 90+18=A+2A
=108=3A
108/3=A
36=A
Answered by
1
Tan2A=cot(A-18)
Tan2A=cot(90-2A)
Tan2A=cot(90-2A)
Cot(A-18)=cot(90-2A)
A+2A=90+18
3A=108
A =108/3=36
Tan2A=cot(90-2A)
Tan2A=cot(90-2A)
Cot(A-18)=cot(90-2A)
A+2A=90+18
3A=108
A =108/3=36
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