Question

anyone plz help me in q.12 !!!​

Answer 1

Answer:

Given:

ΔABC where AD is the median

ΔPQR where PM is the median

and

AB/PQ=BC/QR=AD/PM

To prove that:

ΔABC ~ ΔPQR

Proof:

Since AD is the median,

BD = CD = 1/2 BC

Similarly, PM is the median

QM = RM = 1/2 QR

Given that

AB/PQ = BC/QR = AD/PM

AB/PQ = 2BD/2QM = AD/PM

AB/PQ = BD/QM = AD/PM       .....(1)

Since all 3 sides are proportional

ΔABC ~ ΔPQM     (SSS similarity)

Hence, ∠B=∠Q    (Corresponding angles of similar triangles are equal)  ....(2)

In ΔABC and ΔPQR

∠B=∠Q  (from 2)

AB/PQ = BC/QR  (given)

Hence by SAS similarity

ΔABC ~ ΔPQR

Hence proved

Step-by-step explanation:

sorry for late answer

hehehe

u asked it like 13 hours ago

:)