Question

anyone plz help me out with this.
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Answer 1

hey mate

here is ur answer

Answer 2

SOLUTION

The given equations are:

$= > 4x + py + 8 = 0 .............(1) \\ = > 2x + 2y + 2 = 0 ...........(2)$

Comparing above two equations with standard equations a1x+ b1y+c1=0 &

a2x + b2y+ c2=0 , we get

a1= 4

b1= p

c1= 8

and

a2= 2

b2= 2

c2= 2

For unique solution, we have

$= > \frac{a1}{a2} </u></strong><strong><u>≠</u></strong><strong><u> \frac{b1}{b2} = \frac{4}{2} </u></strong><strong><u>≠</u></strong><strong><u> \frac{p}{2} \\ </u></strong><strong><u>=</u></strong><strong><u> </u></strong><strong><u> > 2p </u></strong><strong><u> </u></strong><strong><u>≠</u></strong><strong><u>8 \\ = > p </u></strong><strong><u>≠</u></strong><strong><u> </u></strong><strong><u>\frac{8}{2} </u></strong><strong><u>≠</u></strong><strong><u>4$

Thus, given lines have a unique solution for all real values of p, except 4.

hope it helps ☺️