Anyone plz solve this equation..
x^2-25=(x-25)^2 and find the value of x. I will surely mark it as the brainliest ans. Only if it is correct. Correct ans only. Plz
khushi0501:
are you sure that it is (x-25)^2 and not (x-5)^2
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x^2-25=(x-5)^2
x^2-5^2=(x-5)^2
(x-5)^2=(x-5)^2
therefore LHS=RHS
x^2-5^2=(x-5)^2
(x-5)^2=(x-5)^2
therefore LHS=RHS
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