Math, asked by unknown3839, 3 months ago

Anyone plz solve this


plz dont spam dear :)​

Attachments:

Answers

Answered by Anonymous
4

\huge\fbox\red{S}\fbox\pink{O}\fbox\blue{L}\fbox\green{U}\fbox\blue{T}\fbox\orange{I}\fbox\green{O}\fbox\pink{N}

\pi \: R {}^{2}  + \pi \: r {}^{2}  = 116\pi \\ R {}^{2}  + r {}^{2}  = 116 \\ R - r = 6 \\ \;\large{\boxed{\bf{\red{R = 6 + r}}}} -  - (i)

(6 + r) {}^{2}  + r {}^{2}  = 116 \\ 2r {}^{2}  + 12r + 36 - 116 = 0 \\ r {}^{2}  + 10r - 4r - 40 = 0 \\ (r - 4)(r + 10) = 0 \\ r =  \: 4 \:,  - 10

\sf\colorbox{green}{Now take Positive Sign Value of r and put on 1st Equation }

r = 4cm \: \\ R = 4 + 6 = 10cm

\;\large{\boxed{\bf{\green{R = 10 \: cm}}}} \: is \: the \: ans..

Note : Swipe to left to view Full Sentence /equation....

\sf\blue{hope \: this \: helps \: you!! \: }

@Mahor2111

______________________

Attachments:
Answered by guardianangelx
1

please do refer the attachment above!!

Attachments:
Similar questions