anyone plz solve this que
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★Let f(x)=2x^3 –7x^2 –3x+18
★For x=2, the value of f(x) will be
- f(2)=2(2)^3 –7(2)^2 –3(2)+18
- =16–28–6+18
- =0
★Therefore
- As f(2)=0,(x–2) is a factor of f(x).
★Now, performing long division we have
- Refer to the attachment
★Thus,
- f(x)=(x–2)(2x^2 –3x–9)
- =(x–2)(2x^2–6x+3x–9)
- =(x–2)[2x(x–3)+3(x–3)]
- =(x–2)(x–3)(2x+3)
★Now,
- for f(x)=0
- (x–2)(x–3)(2x+3)=0
★Hence x=2,3 or −3/2
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World Environment Day (WED) is celebrated annually on 5 June and is the United Nations' principal vehicle for encouraging awareness and action for the protection of the environment
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Oh shukr -_-;
Main Achi Hu sis...ap kaise ho..
gud evening
Wait main deti hi apko thanks...:-|
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