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Sin∅+Cos∅=a
Sin∅-Cos∅=b
prove a²+b²=2
(Sin∅+Cos∅)²+(Sin∅-Cos∅)²=RHS
[use (a+b)²=a²+2ab+b² and (a-b)²=a²-2ab+b² equation]
Then,
Sin²∅+2.Sin∅.Cos∅+Cos²∅+Sin²∅-2.Sin∅.Cos∅+Cos²∅ = RHS
Rearrange it
Sin2∅+Cos²∅+Sin²∅+Cos²∅+2.Sin∅.Cos∅-2.Sin∅.Cos∅ = RHS
1+1+0 = RHS [Because Sin²∅+Cos²∅=1]
2=RHS
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