Question

anyone provide me the answer of this question using the method of linear equation in two variable class 10 ​

Answer 1

Hence the fraction is 9/11

Answer 2

Let the numerator be x and denominator be y.

$\frac{x + 1}{ y+ 1} = \frac{5}{6}$

$6(x + 1) = 5(y + 1)$

$6x + 6 = 5y + 5$

This is the first equation

$6x - 5y = - 1$

Now,

$\frac{x - 5}{y - 5} = \frac{2}{3}$

$3(x - 5) = 2(y - 5)$

$3x - 15 = 2y - 10$

This is the second equation

$3x - 2y = 5$

Using method of equating coefficients

$6x - 5y = - 1 \\ 6x - 4y = 10$

$- y = - 11$

$y = 11$

Using value of y in equation 2

$3x - 2 \times 11 = 5$

$3x - 22 = 5$

$3x = 27$

$x = 9$

The fraction is therefore

$\frac{x}{y} = \frac{9}{11}$