Question

Anyone solve the Q.no.7. Those who solve this q. I will mark him as BRAINLIST.

Answer 1

We know that :

Area of trapezium=1/2*height* (sum of parallel sides)

Given height is 15m

Area=300m²

Let one parallel side be x.

So the other side must be 16+x

It is because their difference is 16m.

x-(16m+x)=16m so the two parallel sides are

16m+x and x.

Using the formula:

300m²=1/2*15m*(16+x+x)

==)600m²=15m*(16+2x)

==)16m+2x=600m²/15m

==)16m+2x=40m

==)2x=40m-16m

==)2x=24m

==)x=24m/2

==)x=12m

We called the parallel sides as 16m+x and x.

So they are 12m+16m and 12m

==)28m and 12m

The answer is 12m and 28m

Hope it helps:-)

And wishing you all Happy Diwali:)

Answer 2

Let the parallel sides be x and y

We know that
Area of trapezium =1/2×Sum of parallel sides × perpendicular distance between the parallel sides

Area of trapezium is given to be 300 m2 and perpendicular distance between parallel sides=15m

So,
300=1/2sum of parallel sides×15
Sum of parallel sides=x+y=300/15=40
So we get :
$x + y = 40 \: \: ...eq1$
It is also given that differences in the parallel sides are 16m

$x - y = 16 \: \: ...eq2$
Adding eq1 and 2 we get
2x=56
x=28
y=12

So the parallel sides are 28m and 12m.
Hope this helps :)