Anyone solve the question
It's very urgent
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Answered by
1
Answer:
Step-by-step explanation:
given, angle DAP=90, angle PCB=90, BC=AD
angle APD=angle BPC(opposite angles)
in ΔPCB and ΔPAD
angle PCB=angle PAD=90(given)
BC=AD(given)
angle BPC=angle APD(opp. angles)
by AAS congruence, ΔPCB≅ΔPAD
by cpct: AP=CP
Answered by
1
Answer:
we have to prove that
AP = CP
Step-by-step explanation:
Proof: - In triangle APD and triangle BPC
AD = BC ( given)
angle APD = angle BPC ( vertically opposite angle)
angle A = angle C = 90°
triangle APD ~= triangle BPC ( AAS)
AP = CP ( cpct)
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