Question

Anyone solve the question
It's very urgent​

Answer 1

Answer:

Step-by-step explanation:

given, angle DAP=90, angle PCB=90, BC=AD

angle APD=angle BPC(opposite angles)

in ΔPCB and ΔPAD

angle PCB=angle PAD=90(given)

BC=AD(given)

angle BPC=angle APD(opp. angles)

by AAS congruence, ΔPCB≅ΔPAD

by cpct: AP=CP

Answer 2

Answer:

we have to prove that

AP = CP

Step-by-step explanation:

Proof: - In triangle APD and triangle BPC

AD = BC ( given)

angle APD = angle BPC ( vertically opposite angle)

angle A = angle C = 90°

triangle APD ~= triangle BPC ( AAS)

AP = CP ( cpct)