Question

anyone solve these questions​

Answer 1

Step-by-step explanation:

let n = 1, 3 , 5

where,

f ( n) = 2n + 1

put n = 1

than f = 3

put n = 3

f= 7

put n = 5

f= 11

hence ,

every elements of n is matched with every unique element of f so, it is one to one , onto function