Question

Anyone solve this ......

Answer 1

Answer:

${x}^{2} + {y}^{2} + 2gx + 2fy + c = 0$

Compare the given question with the equation given below

${x }^{2} + {y}^{2} + 2dx + 2hy + c = 0$

Therefore,

d = g and h = f

So centre is (-d,-h) = (-g,-f)

Radius,

$r = \sqrt{ {g}^{2} + {f}^{2} - c }$