Question

Anyone solve this mathematics question​

Answer 1

Step-by-step explanation:

so ADE = 95 deg

so ADC = 180-95 = 85 deg

now ABCD is a cyclic quardilateral

so

angle ABC = 180 -85 = 95

so angle OBC = 95 - 30 = 65 deg

now

OB = OC (sides of BOC and radiuses of circle)

so OBC = OCB = 65 deg

so BOC = 180 - 2(65)

= 180-130= 50

and OB = OA (sides of BOA and radiuses of circle)

so OAB = OBA = 30 deg

so AOB = 180 - 2(30)

= 180 - 60 = 120 deg

so AOC = 120+ 50 = 170 deg

so triangle AOC is an isoceles triangle

in which OA = OC ( radiuses of circle)

OAC=OCA = x deg

so

x + x + 170 = 180

2x = 10

x = 5 deg answer