Math, asked by Anonymous, 11 months ago

ANYONE SOLVE THIS QUESTION​

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Answered by anmol1404
2

Answer:

(i) 8x2y3 by -2xy

Solution:

(i) 8x2y3/-2xy

= (8/-2) x2 - 1y3 - 1 [Using quotient law xm ÷ xn = xm - n]

= -4xy2.

(ii) 35x3yz2 by -7xyz

Solution:

35x3yz2 by -7xyz

= (35/-7) x3 - 1y1 - 1z2 - 1 [Using quotient law xm ÷ xn = xm - n]

= -5 x2y0z1 [y0 = 1]

= -5x2z.

(iii) -15x3yz3 by -5xyz2

Solution:

-15x3yz3 by -5xyz2.

= (-15/-5) x3 - 1y1 - 1z3 - 2. [Using quotient law xm ÷ xn = xm - n].

= 3 x2y0z1 [y0 = 1].

= 3x2z.

II. Division of a Polynomial by a Monomial

Rule:

For dividing a polynomial by a monomial, divide each term of the polynomial by the monomial. We divide each term of the polynomial by the monomial and then simplify.

Divide:

(i) 6x5 + 18x4 - 3x2 by 3x2

Solution:

6x5 + 18x4 - 3x2 by 3x2

= (6x5 + 18x4 - 3x2) ÷ 3x2 6x5/3x2 + 18x4/3x2 - 3x2/3x2

=2x3 + 6x2 - 1.

(ii) 20x3y + 12x2y2 - 10xy by 2xy

Solution:

20x3y + 12x2y2 - 10xy by 2xy

= (20x3y + 12x2y2 - 10xy) ÷ 2xy

= 20x3y/2xy + 12x2y2/2xy - 10xy/2xy

= 10x2 + 6xy

Answered by Anonymous
2

Answer:

hello mate .....

me apko baake ke answer Kal deta hu.....plz behen........

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