Question

Anyone solve this question​

Answer 1

Answer:

Hence proved $x-(y-z)\neq (x-y)-z$.

Step-by-step explanation:

Compute the value of x - (y - z) as follows:

$x-(y-z)=\frac{4}{9}-(\frac{-7}{12}-\frac{-2}{3})=\frac{4}{9}+\frac{7}{12}-\frac{2}{3}=\frac{48+63-252}{108}=-\frac{141}{108}$

Compute the value of (x - y) - z as follows:

$(x-y)-z=(\frac{4}{9}-\frac{-7}{12})-\frac{-2}{3}=\frac{4}{9}+\frac{7}{12}+\frac{2}{3}=\frac{48+63+252}{108}=\frac{363}{108}$

Hence proved $x-(y-z)\neq (x-y)-z$.

Answer 2

Answer:

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