Anyone solve this question????
Answers
Given :-
=> h = 24cm , r1 = 30/2=15cm , r2 = 10/2 = 5cm.
SOLUTION :-
=> As we know that,
=> l = √h²+(r1-r2)²
=> .°. L = √24²+(15-5)²
=> l = √576 + 100
=> l = √676
=> .°. l = 26cm.
=> (I) Volume of bucket = ⅓πh((r1)²+(r2)²+r1r2)
=> ⅓ * 3.14 * 24(15²+5²+15*5)
=> 3.14 * 8 (225+25+75)
=> .°. Volume of bucket = 8164cm³.
=> .°. Quantity of milk = 8164/1000 = 8.164L
=> .°. Cost of 8.164 litres milk = Rs. 20 * 8.164
=> .°. Cost of 8.164 litres milk = Rs. 163.28
=> (II) TSA of bucket ( excluding the upper end)
=> πl(r1+r2)+π(r2)²
=>3.14*26(15+5)+3.14*5²
=> 1632.8 + 78.5
=> .°. TSA of bucket = 1711.3cm².
=> Cost of 100cm² metal sheet = Rs. 10
=> .°. Cost of 1711.3 cm² metal sheet,
=> .°. 1711.3 × 10/100
=>.°.Cost of 1711.3 cm² metal sheet = Rs. 171.13.
Therefore, the cost of metal sheet is Rs. 171.13.
Given
Depth of the frustum = 24 cm
Radius of the top = 15 cm
Radius of the bottom = 5 cm
Volume of bucket = 1/3* πh[(r₁)²+(r₂)²+r₁r₂]
= 1/3 * 3.14 * 24(15²+5²+15*5)
= 3.14 * 8 (225+25+75)
= 8164 cm³
Quantity of milk = 8164/1000
= 8.164L
Cost of 8.164 litres milk = 20 * 8.164
= Rs. 163.28
l = √h²+(r1-r2)²
= √24²+(15-5)²
= √576 + 100
= √676
= 26cm
TSA of bucket ( excluding the upper end) = πl(r1+r2)+π(r2)²
=3.14*26(15+5)+3.14*5²
= 1632.8 + 78.5
= 1711.3cm²
Cost of 100 cm² of a metal sheet = Rs. 10
Cost of metal sheet = 1711.3 × 10/100
= Rs. 171.13