Math, asked by Anonymous, 6 months ago

ANYONE SOLVE THIS QUESTION ...EXPLAIN ALL QUESTION...ND GIVE CORRECT ANSWER......
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Answered by pulakmath007
27

\displaystyle\huge\red{\underline{\underline{Solution}}}

The equation of any line in Slope - Intercept form is

y = mx + c \:  \:  \: .....(1)

Where m is the slope of the line (1)

Now the line (1) passes through ( 0, a)

So

a = 0 + c

 \therefore \: c \:  = a

So the equation (1) reduced to

y = mx + a \:  \:  \:  \:

 \implies \: mx - y + a = 0 \:  \: .....(2)

Now the Perpendicular Distance from (2a 2a) is

\displaystyle \:  | \frac{2am - 2a + a}{ \sqrt{1 +  {m}^{2} } } |  = a

\implies\displaystyle \:  | {2am - a |   = a \sqrt{1 +  {m}^{2} }}

\implies\displaystyle \:  | {2m - 1 |   =  \sqrt{1 +  {m}^{2} }}

Squaring both sides

4 {m}^{2}  - 4m + 1 = 1 +  {m}^{2}

 \implies \: 3 {m}^{2}  - 4m  = 0

 \implies \: m(3 {m}  - 4)  = 0

So

 \displaystyle \: m = 0 \:  ,  \:  \:  \frac{4}{3}

Putting m = 0 in Equation (2)

y \:  = a \:  \:  \: .....(3)

Putting

 \displaystyle \: m =  \frac{4}{3}

in Equation (2) we get

 \displaystyle \:y =   \frac{4}{3} x + a

 \implies \: 3y - 4x = 3a \:  \:  \: .....(4)

Now the equation of a line perpendicular to Equation (4) is

3x + 4y = k \:  \:

It passes through ( 2a, 2a)

So

14a = k

So the line is

3x + 4y = 14a \:  \:  \:  \: ......(5)

Now the point of intersection of Equation (4) & (5) is obtained by solving them

So the point of intersection is

 \displaystyle \: (  \: \frac{6a}{5} , \frac{13a}{5} \:  )

This is one of the feet of the perpendicular

Again the another feet of the perpendicular on the line y = a from the point ( 2a, 2a ) is ( 2a, a )

Now the required line is the line joining the points

 \displaystyle \: (  \: \frac{6a}{5} , \frac{13a}{5} \:  ) \:  \: and \:  \:  (  \: 2a , a\:  )

So the required line is

 \displaystyle \:  \frac{y - a}{x - 2a}  =  \frac{ \frac{13a}{5}  - a}{ \frac{6a}{5}  - 2a}

 \implies \:  \displaystyle \:  \frac{y - a}{x - 2a}  =  \frac{ 8 a}{ - 4a}

 \implies \:  \displaystyle \:  \frac{y - a}{x - 2a}  =   - 2

 \implies \:  y - a =  - 2x + 4a

 \implies \:  y + 2x = 5a

Hence the proof follows

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