Math, asked by wwwronitcom, 1 year ago

Anyone Solve This quickly ( just need to confirm my ans)

Attachments:

RajivShastry: this is equal to x^2

RajivShastry: So x = k(p^2 - 1)

wwwronitcom: thnx dude

wwwronitcom: m k ko baad me common le raa tha

wwwronitcom: that's why ans nai aara tha

wwwronitcom: tysm

RajivShastry: no prob :)

wwwronitcom: you can ans now if you want XD I'll make you brainliest ☺️

RajivShastry: Thanks bro :)

wwwronitcom: ^_^

Answers

Answered by saniyaarora2003

Answer:

x²= k²p⁴+k²+2kp²-4k²p²

Step-by-step explanation:

x²= k²[(p²+1)² - (2p)²]

x²= k²(p⁴+1+2p²-4p²)

x²= k²(p⁴+1-2p²)

x²= k²[(p²-1)²]

x=√k²[(p²-1)²]

x= k(p²-1)

wwwronitcom: identify is a^2+b^2+2ab

wwwronitcom: focus on that 2ab

saniyaarora2003: ok

wwwronitcom: you can ans now if u want XD I'll make u brainlliest

wwwronitcom: ☺️

saniyaarora2003: i hv already answered

wwwronitcom: woops wrong comment☹️

saniyaarora2003: whose?

wwwronitcom: nothing my bad

saniyaarora2003: ok

Answered by RajivShastry

On RHS,

First take k² common from both terms

x² = k² [(p²+1) - (2p)²]

x² = k²[p⁴+1+2p² - 4p²]

x² = k²[p⁴-2p²+1]

x² = k²(p²-1)²

x = k(p²-1)

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