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nitthesh7:
ans +root 8 and -root 8
How explain
=z^2-8
=z^2+0x+0x-8
sorry z
z(z+8)-z(z+8)
Answers
Answered by
1
Hey guys this is your answer
z^2-8=0
(z)^2-(√8)^2=0
Using identity a^2-b^2=(a+b)(a-b)
(z-√8)(z+√8)=0
z=√8or-√8
z^2-8=0
(z)^2-(√8)^2=0
Using identity a^2-b^2=(a+b)(a-b)
(z-√8)(z+√8)=0
z=√8or-√8
Answered by
1
Z^2- 8=0
Z^2=8
Z=√8
So we put z=√8 then you will ans as 0 so √8 is the zero of the polynomial
Z^2-8=0
Z^2=8
Z=√8
So we put z=√8 then you will ans as 0 so √8 is the zero of the polynomial
Z^2-8=0
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