Question

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Answer 1

Answer :-

Given :-

• ∠ ABC = 50°
• ∠ CAE = 79°

To Find :-

• Value of x

Solution :-

∠CAE + ∠CAB = 180° ( Linear pair )

∠CAB + 79° = 180°

∠CAB = 101°

Applying angle sum property of traingle in ∆ ABC :-

⇒ ∠ABC + ∠CAB + ∠ACB = 180°

⇒ 101° + 50° + ∠ACB = 180°

⇒ ∠ACB + 151 = 180°

⇒ ∠ACB = 180 - 151

⇒ ∠ACB = 29°

Now, ED and AC are parallel lines and CD is transversal.

So, ∠ACB = ∠EDC ( corresponding angles )

∠ACB = 29°

∠EDC = x

So,

⇒ x = 29°

Hence, the value of x = 29°

Answer 2

Answer :-

Given :-

∠ ABC = 50°

∠ CAE = 79°

To Find :-

Value of x

Solution :-

∠CAE + ∠CAB = 180° ( Linear pair )

∠CAB + 79° = 180°

∠CAB = 101°

Applying angle sum property of traingle in ∆ ABC :-

⇒ ∠ABC + ∠CAB + ∠ACB = 180°

⇒ 101° + 50° + ∠ACB = 180°

⇒ ∠ACB + 151 = 180°

⇒ ∠ACB = 180 - 151

⇒ ∠ACB = 29°

Now, ED and AC are parallel lines and CD is transversal.

So, ∠ACB = ∠EDC ( corresponding angles )

∠ACB = 29°

∠EDC = x

So,

⇒ x = 29°

Hence, the value of x = 29°