Question

anyone tell me plz its important​

Answer 1

Answer:

Step-by-step explanation:

sin 15 × cos 75 + cos 15 × sin 75 / tan15 × tan 30 × tan35 × tan55 × tan 85

= sin 15 × cos(90-15) + cos(90-75) × sin 75 / tan30 × tan35 × cot35 × tan15 × cot15

= sin15 × sin15 + sin75 + sin75 / 1/√3 ×1

= sin^2 15 + sin^2 75 × √3

= sin^2 15 + cos^2 15 × √3

= 1 ×√3

= √3

Answer 2

(sin15° cos75° + cos15°sin75°)

tan5° tan35°tan55°tan30°tan85

sin(15+75).

tan5° cot5°tan35°cot35°tan30°

1.

tan30°

sqrt3

formula

tan(90 - 5) = cot5°= tan85°

tan(90 - 35) = cot35°= tan55°

tan30° = 1/sqrt3

tanA *cotA = 1

sinAcosB + cosAsinB = sin(A+B)

hope it may helps you:-)