Question

Anyone who can solve it?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Hello Mate!

9. Given : < FGO = < HGO.

To prove : Chord AB = Chord CD

To construct : Draw perpendicular bisector from O to respective chords.

Proof : In ∆OFG and ∆OHG,

< OFG = < OHG ( 90° each )

< FGO = < HGO ( Given )

OG = OG ( Common )

Hence ∆FGO and ∆HGO are congruent by AAS congruency.

OF = OH

This means that chords are equidistant from center. Hence by theorum Chord AB = Chord CD.

Hence proved.

10. Given : The shape is circle or C(O,r) where triangles are drawn ion same segment.

To prove : < BAD = < BCD.

Proof : (i) By theorum we know that,

< BAD = ½ < BOD and < BCD = ½ < BOD

Hence < BAD = < BCD.

(ii) By theorum we know that,

< BAD = ½ < BOD and < BCD = ½ < BOD

Hence < BAD = < BCD.

Therefore in both cases we got, < BAD = < BCD.

Hence proved.

Q.E.D

Have great future ahead!