anyone who can solve the 6th sum...
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side=8cm
area=(√3/4)* side^2
area=(√3/4)*8*8
=√3*2*8
=√3*16
=16√3cm^2
by Pythagoras theorem
hypotenuse ^2=base^2+height^2
8^2=4^2+ height^2
64=16+height^2
height^2=64-16
height^2=48
height=√48
height=4√3cm
area=(√3/4)* side^2
area=(√3/4)*8*8
=√3*2*8
=√3*16
=16√3cm^2
by Pythagoras theorem
hypotenuse ^2=base^2+height^2
8^2=4^2+ height^2
64=16+height^2
height^2=64-16
height^2=48
height=√48
height=4√3cm
Gurveer08:
nice answer
SOOO SOOORRRYYYY DEAR BUT I CANT
BECAUSE THE ONE WHO PUT QUESTION CAN ONLY MARK BRAINLIEST TO ANYONES ANSWER
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