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Answer:
Hi herw is your answer
Step-by-step explanation:
(7√3/√10 + √3) - (2√5/√6 + √5) - (3√2/√15 + 3√2)
Let,
x = (7√3/√10 + √3)
y = (2√5/√6 + √5)
z = (3√2/√15 + 3√2)
so,
→ x = (7√3/√10 + √3)
rationalising the denominator,
→ x = 7√3 * (√10 - √3) / (√10 + √3)(√10 - √3)
→ x = 7√3 * (√10 - √3) / (10 - 3)
→ x = 7√3 * (√10 - √3) / 7
→ x = (√30 - 3)
now,
→ y = (2√5/√6 + √5)
rationalising the denominator,
→ y = 2√5 * (√6 - √5) / (√6 + √5)(√6 - √5)
→ y = 2√5(√6 - √5) / (6 - 5)
→ y = 2√30 - 2 * 5
→ y = (2√30 - 10)
and,
→ z = (3√2/√15 + 3√2)
→ z = 3√2 * (√15 - 3√2) / (√15 + 3√2)(√15 - 3√2)
→ z = 3√2(√15 - 3√2) / (15 - 18)
→ z = (-√2(√15 - 3√2)
→ z = (-√30 + 6)
then,
→ x - y - z
→ (√30 - 3) - (2√30 - 10) - (-√30 + 6)
→ √30 - 2√30 + √30 - 3 + 10 - 6
→ 2√30 - 2√30 + 10 - 9
→ 10 - 9
→ 1 (Ans.)
Please mark the answer as brainlist please