Math, asked by juanjuel27, 2 days ago

ANYONE WHO WANTS TO BE BRANLIEST ANSWER THIS SMALL QUESTION

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Answered by srivastavaseem
1

Answer:

Hi herw is your answer

Step-by-step explanation:

(7√3/√10 + √3) - (2√5/√6 + √5) - (3√2/√15 + 3√2)

Let,

x = (7√3/√10 + √3)

y = (2√5/√6 + √5)

z = (3√2/√15 + 3√2)

so,

→ x = (7√3/√10 + √3)

rationalising the denominator,

→ x = 7√3 * (√10 - √3) / (√10 + √3)(√10 - √3)

→ x = 7√3 * (√10 - √3) / (10 - 3)

→ x = 7√3 * (√10 - √3) / 7

→ x = (√30 - 3)

now,

→ y = (2√5/√6 + √5)

rationalising the denominator,

→ y = 2√5 * (√6 - √5) / (√6 + √5)(√6 - √5)

→ y = 2√5(√6 - √5) / (6 - 5)

→ y = 2√30 - 2 * 5

→ y = (2√30 - 10)

and,

→ z = (3√2/√15 + 3√2)

→ z = 3√2 * (√15 - 3√2) / (√15 + 3√2)(√15 - 3√2)

→ z = 3√2(√15 - 3√2) / (15 - 18)

→ z = (-√2(√15 - 3√2)

→ z = (-√30 + 6)

then,

→ x - y - z

→ (√30 - 3) - (2√30 - 10) - (-√30 + 6)

→ √30 - 2√30 + √30 - 3 + 10 - 6

→ 2√30 - 2√30 + 10 - 9

→ 10 - 9

→ 1 (Ans.)

Please mark the answer as brainlist please

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