∠aob=90° ∠cba=30° ∠cab =???
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Therefore Dont Even Think Of Applying Angle Sum Property
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∠BCA = 1/2∠BOA --- Angle subtended by the same arc to the centre is double the angle subtended at the circumference
∠BCA = 1/2 * 90
∠BCA = 45°
∠BCA + ∠CAB + ∠ABC = 180° - -Angle Sum Property
45 + ∠CAB + 30 = 180
∠CAB = 180 - 75
∠CAB = 105°
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∠BCA = 1/2 * 90
∠BCA = 45°
∠BCA + ∠CAB + ∠ABC = 180° - -Angle Sum Property
45 + ∠CAB + 30 = 180
∠CAB = 180 - 75
∠CAB = 105°
Mark This Brainliest If This Helped u
Thankx
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correct answers
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