Question

AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. find the value of angle ACD+BED

Answer 1

Answer:

270

Step-by-step explanation:

Join AE,

Since, ACDE is a cyclic quadrilateral .

∴ ∠ACD + ∠AED = 180° ---- i)

Also, ∠AEB = 90° ---- ii) [angle in semi circle]

On adding Eqs. (i) and (ii) , we get

∠ACD + ∠(AED + ∠AEB = 180° + 90°

⇒ ∠ACD + ∠BED = 270°

Hence , the value of (∠ACD + ∠BED) is 270