Question

Aob is a diameter of the circle .C,d,e three point on semicircle then prove angle acd+angle bed

Answer 1

Answer:

Step-by-step explanation:

Join AE,  

Since, ACDE is a cyclic quadrilateral .

∴ ∠ACD + ∠AED = 180° ---- i)  

Also, ∠AEB = 90° ---- ii)   [angle in semi circle]  

On adding Eqs. (i) and (ii) , we get  

∠ACD + ∠(AED + ∠AEB  = 180° + 90°  

⇒ ∠ACD + ∠BED = 270°  

Hence , the value of (∠ACD + ∠BED) is 270