AOB is a sector of a circle of radius 4cm subtending an angle of 45 dgree at the center O of the circle. Area of the sector in CM square.,is
Answers
Answer:
Here, r=4cm and θ=30o
⇒ Area of the sector =360oθ(πr2)
Where, θ is angle subtended at a center.
πr2 is area of a circle.
⇒ Area of the sector =360o30o×π×(4)2
∴ Area of the sector =34πcm2
Answer:
Area of sector = 6.28 cm²
Explanation:
Given: AOB is a sector, radius of circle= 4 cm, angle subtended at the center θ= 45°.
To find: Area of the sector.
Solution:
The area of sector is the space inside the section of the circle formed by two radii and an arc. It is a fraction of the area of the entire circle.
Area of sector = πr²× θ/360°, θ is the angle of the sector and r is the radius of the circle.
Area of sector = π ×4×4 ×45°/360°
=π ×4×4×1/8
= π×4/2
= π×2
= 3.14×2
= 6.28cm²
∴ Area of the sector = 6.28 cm².
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