Question

AOB is a sector of a circle of radius 4cm subtending an angle of 45 dgree at the center O of the circle. Area of the sector in CM squ
are.,is​

Answer 1

Answer:

formula. °/360 x π r^2

(45/360) x 22/7 x16

6.2 cm

Answer 2

Given,

Radius of the circle = 4 cm

AOB sector subtends an angle of 45°

To find,

The area of the sector (in cm²).

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Now,

A complete circle subtends = 360°

Let,

Total circle = 1 part

So,

360° is subtended by = 1 part of circle

1° is subtended by = 1/360 part of circle

45° is subtended by = (1×45)/360 = ⅛ part of circle

So, to calculate the the area of sector AOB, we need to calculate the ⅛ part of the area of the whole circle.

Area of the whole circle :

= π × (radius)²

= [(22/7) × (4)²] cm²

= [(22/7) × 16] cm²

Area of the AOB sector :

= ⅛ × Area of the whole circle

= [⅛ × (22/7) × 16] cm²

= 6.28 cm² (approx.)

Hence, the area of AOB sector is approximately 6.28 cm².