AOB is a straight line and the ray OC stands on it . If angle AOC = (2x -50)° and angle BOC = (3x +20)° , find the value of x.
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Given:-
AOC=2x-50°
BOC=3x+20°
AOC+BOC=180° (Linear Pair}
(2x-50)+(3x+20)=180°
5x-30=180°
5x=180°+30°
5x=210°
x=210/5
x=42°
AOC=2x-50°
=2(42)-50
=84-50
=34°
BOC=3x+20
=3(42)+20
=126+20
=146°
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