Question

aob is a straight line. in which,3 angles are lying aod,doc and cob.if angledoc is 45°. find aod(x+15)° and cob(x+30)°​
PLEASE SOLVE STEP BY STEP

Answer 1

Answer:

Given the angle doc is 45

Step-by-step explanation:

We know that the sum of angles in a triangle is 180degrees.

And then angle aod+cob+45=180.

i.e,(x+15)+(x+30)+45=180.

(x+15)+(x+30)=180-45

(x+15)+(x+30)=135

2x+30x+15x+15x30=135

xsquare+45x+450=135

xsquare+45x+450-135=0

xsquare+45x+315=0

After this just do fractionsation on L.H.S

And with that we get x

equate that in the equation above that may be aod(x+15) or cob(x+30).

Then add all the answer u get

That should be 180

Since the sum of all the angles in a triangle is 180 degrees.

Check my anwers with other also.