AOB is a straight line. OP bisects angle BOC and OQ bisect angle AOC show that angle POQ is a right angle.
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∠POQ= ∠POC+COQ
1/2 ∠BOC+1/2 ∠AOC
∵OP Bisects ∠AOC
∵ ∠POC=1/2 ∠BOC
∵OQ bisects ∠AOC
∵ ∠COQ=1/2 AOC
1/2 (∠BOC+ ∠AOC)
1/2 180 ° (linear pair)
=90 °
Hence proved
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