AOB IS LINE, od bisect angle AOC and OE bisect angle BOC show that angle DOE is right angle
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mate here is your short answer very easy
see
OD is bisector of AOC
therefore, angle AOD = DOC
and similarly
OE is bisector of BOC
therefore,angle COE = EOB
Now
let,
angle AOD = A , DOC = B , COE = C and EOB = D
and, A = B and C = D ( because OD and OE are angle bisectors)
therefore,
we know that,sum of all interior angles is 180°
So,
AOD + DOC + COE + EOB = 180°
A + B + C + D = 180°
A + A + B + B = 180°
2A + 2B = 180°
2 ( A+B ) = 180°
A + B = 180° / 2
A + B = 90°
DOC + COE = 90°
DOE = 90°
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