Question

AOB is the diameter of a circle with centre O. AC and BC are two chords measuring 3cm and 4cm respectively. Find the area of the minor segment formed by chords AC and BC . (Pie = 3.14

Answer 1

Answer:

Step-by-step explanation:

Area of semicircle ABC= πr2/2

Radius = x

In triangle BOC

Oc2 + ob2= bc2

X2+ X2 = 16

X2= 8

X= 2√2cm

Area of semicircle= πr2/2

= 12.56cm2

Area of triangle= 1/2*b*h

= 8cm2

area of segment= area of semicircle- area of triangletriangle

= area= 4.56cm2