AOB is the diameter of a circle with centre O. AC and BC are two chords measuring 3cm and 4cm respectively. Find the area of the minor segment formed by chords AC and BC . (Pie = 3.14
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Answer:
Step-by-step explanation:
Area of semicircle ABC= πr2/2
Radius = x
In triangle BOC
Oc2 + ob2= bc2
X2+ X2 = 16
X2= 8
X= 2√2cm
Area of semicircle= πr2/2
= 12.56cm2
Area of triangle= 1/2*b*h
= 8cm2
area of segment= area of semicircle- area of triangletriangle
= area= 4.56cm2
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