Question

AOBC is a rectangle whose three vertices are (4,0),B(0,3),and 0(0,0)then its length of the diagnol is

Answer 1

Answer:

Step-by-step explanation:

in rectangle AOBC, diagonals are AB and OC

AB = {(4-0)^2  +  (0-3)^2}^1/2

AB = {16 + 9}^1/2

AB = {25}^1/2

AB = 5 units

length of the diagonal = 5 units

Answer 2

Answer:

Step-by-step explanation:

In a rectangle the 2 diagonals are equal and bisect each other.

Since the diagonals are equal, in the given rectangle, AB=OC

AB=√(x1-x2)²+(y1-y2)²

Here, x1=4 and x2=0     and     y1=0 and y2=3

Therefore, AB=√(4-0)²-(0-3)²

                       =√16+9=√25=5units

Therefore, the length of the diagonal of the rectangle AOBC is 5units.  

THUMBS UP!!!