Question

AOBC is a rectangle whose three vertices are A (0, 3) O (O, 0) and B (5, 0). The length of its diagonal is

Answer 1

the diagonal of rectangle is √34 units

Answer 2

Given

AOBC is a rectangle

It has 3 vertices, they are A(0 , 3) O (0 , 0) and B (5 , 0)

Required to find

Length of the diagonal.

Solution

\sf ab = \sqrt{ { (x_{2} - { x_{1})} }^{2} } + (y_{2} - { y_{1})}^{2}ab=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

\sf \implies \sqrt{ {(5 - 0)}^{2} } + {(0 - 3)}^{2}⟹

(5−0)

2

+(0−3)

2

\sf \implies \sqrt{ {5}^{2} } + { (- 3)}^{2}⟹

5

2

+(−3)

2

\sf \implies \sqrt{25} + 9⟹

25

+9

\implies \sf \sqrt{34 \:} units⟹

34

units

\tt \underline\color{teal}{Note}

Note

•You can find diagonal if you have the width and the height.

•A recrangle has 2 diagonals , each one is line segment drawn between the opposite vertices of the rectangle.

•Diagonals are always congruent