Question

AOKAT HAI TO ISE SOLVE KAR KE DHOKAOa beam of electron is accelerated from rest by a potential difference V 1.the de broglie wavelength of the electron is lambda. if the electrons are further accelerated by voltage V 2,the de broglie wavelength become lambda/2. find the ratio of V 1/V2 [100percent correct quistion] answer is=1/3

Answer 1

Answer:

V1/V2=1/4

Explanation:

lambda=12.26/√V1

lambda/2=12.26/√V2

V1/V2=1/4

Answer 2

Answer: 1/3

Explanation:λ1=12.27/$\sqrt{v1}$

λ2=12.27/$\sqrt{v1+v2}$

Taking ratio of λ1 and λ2 = λ1/λ2 =λ/λ/2 =2/1

2/1=$\sqrt{v1+v2}$/$\sqrt{v1}$  (i)

taking square on both the sides

4/1=v1+v2/v1 = 4v1=v1+v2 = 3v1 = v2

therefore v1/v2 =1/3