Question

AP=12 cm
PB=8 cm AQ=15 cm QC=10 cm​

Solve this.

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Answer 1

Answer:

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Explanation:

In ΔABC,

P and Q are points on side AB and AC such that PQ||BC

Here, AP = 12cm, PB = 8cm, AQ = 9 cm .

[ If a line is drawn parallel to the one side of a triangle to intersect the other two sides in distinct points, The other two sides are divided in the same ratio ]

Therefore,

AP / PB = AQ / QC

Let the QC be x cm

12/8 = 9/x

[ By cross multiply ]

12x = 72

x = 72/12

x = 6cm

Now,

We have to find AC

Therefore,

AC = AQ + QC

AC = 9 + 6

AC = 15cm

Hence, The value of AC is 15 cm ..

Answer 2

Answer:

ac = 15 ans

we get

Explanation:

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