French, asked by vivek887, 9 months ago

ap 3,8,13,25,find 20th term​

Answers

Answered by mastermimd2
1

Explanation:

Given series is 3, 8, 13, ...... 253

Given series is 3, 8, 13, ...... 253 here, first term , a = 3

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1)

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.now we know, mth term from last =last term - mth term + 1

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.now we know, mth term from last =last term - mth term + 1 so, 20th term from last = 51 - 20 + 1 = 32

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.now we know, mth term from last =last term - mth term + 1 so, 20th term from last = 51 - 20 + 1 = 32 hence, 20th from last = 32th term from first

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use => 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.now we know, mth term from last =last term - mth term + 1 so, 20th term from last = 51 - 20 + 1 = 32 hence, 20th from last = 32th term from first use , T

= 3 + 31 × 5 = 3 + 155 = 158

= 3 + 31 × 5 = 3 + 155 = 158 hence , 20th term from last = 158

Answered by manu9035
1

Answer:

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